3[x-2(x+1)]=x+4

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Solution for 3[x-2(x+1)]=x+4 equation:


Simplifying
3[x + -2(x + 1)] = x + 4

Reorder the terms:
3[x + -2(1 + x)] = x + 4
3[x + (1 * -2 + x * -2)] = x + 4
3[x + (-2 + -2x)] = x + 4

Reorder the terms:
3[-2 + x + -2x] = x + 4

Combine like terms: x + -2x = -1x
3[-2 + -1x] = x + 4
[-2 * 3 + -1x * 3] = x + 4
[-6 + -3x] = x + 4

Reorder the terms:
-6 + -3x = 4 + x

Solving
-6 + -3x = 4 + x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.
-6 + -3x + -1x = 4 + x + -1x

Combine like terms: -3x + -1x = -4x
-6 + -4x = 4 + x + -1x

Combine like terms: x + -1x = 0
-6 + -4x = 4 + 0
-6 + -4x = 4

Add '6' to each side of the equation.
-6 + 6 + -4x = 4 + 6

Combine like terms: -6 + 6 = 0
0 + -4x = 4 + 6
-4x = 4 + 6

Combine like terms: 4 + 6 = 10
-4x = 10

Divide each side by '-4'.
x = -2.5

Simplifying
x = -2.5

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